Distance from Langley Park to San Lazzaro di Savena
The shortest distance (air line) between Langley Park and San Lazzaro di Savena is 4,342.16 mi (6,988.03 km).
How far is Langley Park from San Lazzaro di Savena
Langley Park is located in Maryland, United States within 38° 59' 22.92" N -77° 1' 9.12" W (38.9897, -76.9808) coordinates. The local time in Langley Park is 01:06 (25.08.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 07:06 (25.08.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,342.16 miles which is equal to 6,988.03 km.
Langley Park, Maryland, United States
Related Distances from Langley Park
San Lazzaro di Savena, Bologna, Italy