Distance from Lake in the Hills to San Angelo
The shortest distance (air line) between Lake in the Hills and San Angelo is 997.79 mi (1,605.79 km).
How far is Lake in the Hills from San Angelo
Lake in the Hills is located in Illinois, United States within 42° 11' 28.68" N -89° 39' 8.28" W (42.1913, -88.3477) coordinates. The local time in Lake in the Hills is 00:55 (20.12.2025)
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 00:55 (20.12.2025)
The calculated flying distance from San Angelo to San Angelo is 997.79 miles which is equal to 1,605.79 km.
Lake in the Hills, Illinois, United States
Related Distances from Lake in the Hills
San Angelo, Texas, United States