Distance from Lake Stevens to Sveti Ivan Zelina
The shortest distance (air line) between Lake Stevens and Sveti Ivan Zelina is 5,474.79 mi (8,810.83 km).
How far is Lake Stevens from Sveti Ivan Zelina
Lake Stevens is located in Washington, United States within 48° 0' 8.64" N -123° 54' 16.92" W (48.0024, -122.0953) coordinates. The local time in Lake Stevens is 00:29 (29.07.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 09:29 (29.07.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,474.79 miles which is equal to 8,810.83 km.
Lake Stevens, Washington, United States
Related Distances from Lake Stevens
Sveti Ivan Zelina, Zagrebačka županija, Croatia