Distance from Lake Oswego to Tassin-la-Demi-Lune
The shortest distance (air line) between Lake Oswego and Tassin-la-Demi-Lune is 5,371.63 mi (8,644.80 km).
How far is Lake Oswego from Tassin-la-Demi-Lune
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 19:38 (09.08.2025)
Tassin-la-Demi-Lune is located in Rhône, France within 45° 45' 50.4" N 4° 46' 48" E (45.7640, 4.7800) coordinates. The local time in Tassin-la-Demi-Lune is 04:38 (10.08.2025)
The calculated flying distance from Tassin-la-Demi-Lune to Tassin-la-Demi-Lune is 5,371.63 miles which is equal to 8,644.80 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
Tassin-la-Demi-Lune, Rhône, France