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      Distance from Lake Oswego to San Vicente de Baracaldo

      The shortest distance (air line) between Lake Oswego and San Vicente de Baracaldo is 5,278.50 mi (8,494.92 km).

      How far is Lake Oswego from San Vicente de Baracaldo

      Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 09:32 (31.08.2025)

      San Vicente de Baracaldo is located in Bizkaia, Spain within 43° 17' 49.92" N -3° 0' 29.88" W (43.2972, -2.9917) coordinates. The local time in San Vicente de Baracaldo is 18:32 (31.08.2025)

      The calculated flying distance from San Vicente de Baracaldo to San Vicente de Baracaldo is 5,278.50 miles which is equal to 8,494.92 km.

      Lake Oswego, Oregon, United States

      Related Distances from Lake Oswego

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      Lake Oswego to Philadelphia (Pennsylvania)2,407.85 mi (3,875.05 km)
      Lake Oswego to New York (New York)2,445.96 mi (3,936.39 km)
      Lake Oswego to Brooklyn (New York)2,446.04 mi (3,936.52 km)
      Lake Oswego to Queens (New York)2,450.46 mi (3,943.64 km)
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      San Vicente de Baracaldo, Bizkaia, Spain

      Related Distances to San Vicente de Baracaldo