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      Distance from Lake Oswego to San Andres de Llevaneras

      The shortest distance (air line) between Lake Oswego and San Andres de Llevaneras is 5,542.15 mi (8,919.23 km).

      How far is Lake Oswego from San Andres de Llevaneras

      Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 09:23 (02.09.2025)

      San Andres de Llevaneras is located in Barcelona, Spain within 41° 34' 23.88" N 2° 28' 58.08" E (41.5733, 2.4828) coordinates. The local time in San Andres de Llevaneras is 18:23 (02.09.2025)

      The calculated flying distance from San Andres de Llevaneras to San Andres de Llevaneras is 5,542.15 miles which is equal to 8,919.23 km.

      Lake Oswego, Oregon, United States

      Related Distances from Lake Oswego

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      Lake Oswego to Dallas (Texas)1,630.05 mi (2,623.31 km)
      Lake Oswego to St. Louis (Missouri)1,717.39 mi (2,763.87 km)
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      Lake Oswego to Washington (District of Columbia)2,350.05 mi (3,782.05 km)
      Lake Oswego to Baltimore (Maryland)2,357.37 mi (3,793.82 km)
      Lake Oswego to Philadelphia (Pennsylvania)2,407.85 mi (3,875.05 km)
      Lake Oswego to New York (New York)2,445.96 mi (3,936.39 km)
      Lake Oswego to Brooklyn (New York)2,446.04 mi (3,936.52 km)
      Lake Oswego to Queens (New York)2,450.46 mi (3,943.64 km)
      Lake Oswego to Tampa (Florida)2,498.61 mi (4,021.13 km)
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      San Andres de Llevaneras, Barcelona, Spain

      Related Distances to San Andres de Llevaneras