Distance from Lake Arbor to Sint-Kruis
The shortest distance (air line) between Lake Arbor and Sint-Kruis is 3,800.22 mi (6,115.86 km).
How far is Lake Arbor from Sint-Kruis
Lake Arbor is located in Maryland, United States within 38° 54' 37.8" N -77° 10' 10.56" W (38.9105, -76.8304) coordinates. The local time in Lake Arbor is 01:42 (26.07.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 07:42 (26.07.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 3,800.22 miles which is equal to 6,115.86 km.
Lake Arbor, Maryland, United States
Related Distances from Lake Arbor
Sint-Kruis, Arr. Brugge, Belgium