Distance from Koekelberg to Warrensville Heights
The shortest distance (air line) between Koekelberg and Warrensville Heights is 3,924.66 mi (6,316.12 km).
How far is Koekelberg from Warrensville Heights
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 06:33 (24.12.2025)
Warrensville Heights is located in Ohio, United States within 41° 26' 10.68" N -82° 28' 40.08" W (41.4363, -81.5222) coordinates. The local time in Warrensville Heights is 00:33 (24.12.2025)
The calculated flying distance from Warrensville Heights to Warrensville Heights is 3,924.66 miles which is equal to 6,316.12 km.
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium
Related Distances from Koekelberg
Warrensville Heights, Ohio, United States