Distance from Koekelberg to Shenandoah
The shortest distance (air line) between Koekelberg and Shenandoah is 4,836.92 mi (7,784.28 km).
How far is Koekelberg from Shenandoah
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 10:14 (22.12.2025)
Shenandoah is located in Louisiana, United States within 30° 24' 6.84" N -92° 59' 52.8" W (30.4019, -91.0020) coordinates. The local time in Shenandoah is 03:14 (22.12.2025)
The calculated flying distance from Shenandoah to Shenandoah is 4,836.92 miles which is equal to 7,784.28 km.
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium
Related Distances from Koekelberg
Shenandoah, Louisiana, United States