Distance from Koekelberg to Sandy Springs
The shortest distance (air line) between Koekelberg and Sandy Springs is 4,393.21 mi (7,070.19 km).
How far is Koekelberg from Sandy Springs
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 10:26 (22.12.2025)
Sandy Springs is located in Georgia, United States within 33° 56' 11.76" N -85° 37' 46.92" W (33.9366, -84.3703) coordinates. The local time in Sandy Springs is 04:26 (22.12.2025)
The calculated flying distance from Sandy Springs to Sandy Springs is 4,393.21 miles which is equal to 7,070.19 km.
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium
Related Distances from Koekelberg
Sandy Springs, Georgia, United States