Distance from Koekelberg to Ruskin
The shortest distance (air line) between Koekelberg and Ruskin is 4,622.57 mi (7,439.31 km).
How far is Koekelberg from Ruskin
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 07:03 (22.12.2025)
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 01:03 (22.12.2025)
The calculated flying distance from Ruskin to Ruskin is 4,622.57 miles which is equal to 7,439.31 km.
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium
Related Distances from Koekelberg
Ruskin, Florida, United States