Distance from Koekelberg to Palmetto Bay
The shortest distance (air line) between Koekelberg and Palmetto Bay is 4,639.13 mi (7,465.95 km).
How far is Koekelberg from Palmetto Bay
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 20:37 (20.12.2025)
Palmetto Bay is located in Florida, United States within 25° 37' 18.84" N -81° 40' 40.44" W (25.6219, -80.3221) coordinates. The local time in Palmetto Bay is 14:37 (20.12.2025)
The calculated flying distance from Palmetto Bay to Palmetto Bay is 4,639.13 miles which is equal to 7,465.95 km.
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium
Related Distances from Koekelberg
Palmetto Bay, Florida, United States