Distance from Koekelberg to Martinsville
The shortest distance (air line) between Koekelberg and Martinsville is 4,078.75 mi (6,564.11 km).
How far is Koekelberg from Martinsville
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 11:01 (04.01.2026)
Martinsville is located in Virginia, United States within 36° 40' 57.36" N -80° 8' 11.04" W (36.6826, -79.8636) coordinates. The local time in Martinsville is 05:01 (04.01.2026)
The calculated flying distance from Martinsville to Martinsville is 4,078.75 miles which is equal to 6,564.11 km.
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium
Related Distances from Koekelberg
Martinsville, Virginia, United States