Distance from Koekelberg to Martinsburg
The shortest distance (air line) between Koekelberg and Martinsburg is 3,874.18 mi (6,234.90 km).
How far is Koekelberg from Martinsburg
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 07:45 (19.12.2025)
Martinsburg is located in West Virginia, United States within 39° 27' 29.52" N -78° 1' 20.64" W (39.4582, -77.9776) coordinates. The local time in Martinsburg is 01:45 (19.12.2025)
The calculated flying distance from Martinsburg to Martinsburg is 3,874.18 miles which is equal to 6,234.90 km.
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium
Related Distances from Koekelberg
Martinsburg, West Virginia, United States