Distance from Koekelberg to Johnston
The shortest distance (air line) between Koekelberg and Johnston is 4,371.20 mi (7,034.77 km).
How far is Koekelberg from Johnston
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 15:18 (18.12.2025)
Johnston is located in Iowa, United States within 41° 41' 27.6" N -94° 16' 35.76" W (41.6910, -93.7234) coordinates. The local time in Johnston is 08:18 (18.12.2025)
The calculated flying distance from Johnston to Johnston is 4,371.20 miles which is equal to 7,034.77 km.
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium