Distance from Jeffersontown to Asenovgrad
The shortest distance (air line) between Jeffersontown and Asenovgrad is 5,380.33 mi (8,658.80 km).
How far is Jeffersontown from Asenovgrad
Jeffersontown is located in Kentucky, United States within 38° 12' 17.64" N -86° 25' 47.64" W (38.2049, -85.5701) coordinates. The local time in Jeffersontown is 21:34 (26.07.2025)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 04:34 (27.07.2025)
The calculated flying distance from Asenovgrad to Asenovgrad is 5,380.33 miles which is equal to 8,658.80 km.
Jeffersontown, Kentucky, United States