Distance from Jefferson Valley-Yorktown to Sint-Andries
The shortest distance (air line) between Jefferson Valley-Yorktown and Sint-Andries is 3,568.28 mi (5,742.59 km).
How far is Jefferson Valley-Yorktown from Sint-Andries
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 02:11 (28.07.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 08:11 (28.07.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 3,568.28 miles which is equal to 5,742.59 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Sint-Andries, Arr. Brugge, Belgium