Distance from Jefferson Valley-Yorktown to Roeselare
The shortest distance (air line) between Jefferson Valley-Yorktown and Roeselare is 3,572.21 mi (5,748.92 km).
How far is Jefferson Valley-Yorktown from Roeselare
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 05:28 (30.07.2025)
Roeselare is located in Arr. Roeselare, Belgium within 50° 56' 40.92" N 3° 7' 23.88" E (50.9447, 3.1233) coordinates. The local time in Roeselare is 11:28 (30.07.2025)
The calculated flying distance from Roeselare to Roeselare is 3,572.21 miles which is equal to 5,748.92 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Roeselare, Arr. Roeselare, Belgium