Distance from Jefferson Valley-Yorktown to Oudenburg
The shortest distance (air line) between Jefferson Valley-Yorktown and Oudenburg is 3,561.28 mi (5,731.33 km).
How far is Jefferson Valley-Yorktown from Oudenburg
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 18:55 (26.07.2025)
Oudenburg is located in Arr. Oostende, Belgium within 51° 10' 59.88" N 3° 0' 0" E (51.1833, 3.0000) coordinates. The local time in Oudenburg is 00:55 (27.07.2025)
The calculated flying distance from Oudenburg to Oudenburg is 3,561.28 miles which is equal to 5,731.33 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Oudenburg, Arr. Oostende, Belgium