Distance from Jefferson Valley-Yorktown to Opglabbeek
The shortest distance (air line) between Jefferson Valley-Yorktown and Opglabbeek is 3,668.74 mi (5,904.26 km).
How far is Jefferson Valley-Yorktown from Opglabbeek
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 15:11 (26.07.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 21:11 (26.07.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 3,668.74 miles which is equal to 5,904.26 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Opglabbeek, Arr. Maaseik, Belgium