Distance from Jefferson Valley-Yorktown to Lyaskovets
The shortest distance (air line) between Jefferson Valley-Yorktown and Lyaskovets is 4,758.62 mi (7,658.26 km).
How far is Jefferson Valley-Yorktown from Lyaskovets
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 17:02 (31.07.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 00:02 (01.08.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 4,758.62 miles which is equal to 7,658.26 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Lyaskovets, Veliko Tarnovo, Bulgaria