Distance from Jefferson Valley-Yorktown to Koekelberg
The shortest distance (air line) between Jefferson Valley-Yorktown and Koekelberg is 3,623.21 mi (5,831.00 km).
How far is Jefferson Valley-Yorktown from Koekelberg
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 03:10 (26.07.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 09:10 (26.07.2025)
The calculated flying distance from Koekelberg to Koekelberg is 3,623.21 miles which is equal to 5,831.00 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium