Distance from Jefferson Valley-Yorktown to Celakovice
The shortest distance (air line) between Jefferson Valley-Yorktown and Celakovice is 4,057.59 mi (6,530.06 km).
How far is Jefferson Valley-Yorktown from Celakovice
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 14:05 (01.08.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 20:05 (01.08.2025)
The calculated flying distance from Celakovice to Celakovice is 4,057.59 miles which is equal to 6,530.06 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Celakovice, Středočeský kraj, Czechia