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      Distance from Jefferson Hills to Sint-Katelijne-Waver

      The shortest distance (air line) between Jefferson Hills and Sint-Katelijne-Waver is 3,916.42 mi (6,302.87 km).

      How far is Jefferson Hills from Sint-Katelijne-Waver

      Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 06:20 (30.07.2025)

      Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 12:20 (30.07.2025)

      The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 3,916.42 miles which is equal to 6,302.87 km.

      Jefferson Hills, Pennsylvania, United States

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      Jefferson Hills to Baltimore (Maryland)188.90 mi (304.00 km)
      Jefferson Hills to Detroit (Michigan)218.84 mi (352.19 km)
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      Jefferson Hills to Brooklyn (New York)315.40 mi (507.58 km)
      Jefferson Hills to New York (New York)316.84 mi (509.90 km)
      Jefferson Hills to Queens (New York)323.72 mi (520.97 km)
      Jefferson Hills to Chicago (Illinois)417.62 mi (672.09 km)
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      Sint-Katelijne-Waver, Arr. Mechelen, Belgium

      Related Distances to Sint-Katelijne-Waver