Distance from Jefferson Hills to Diepenbeek
The shortest distance (air line) between Jefferson Hills and Diepenbeek is 3,955.93 mi (6,366.46 km).
How far is Jefferson Hills from Diepenbeek
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 23:15 (23.07.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 05:15 (24.07.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,955.93 miles which is equal to 6,366.46 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Diepenbeek, Arr. Hasselt, Belgium