Distance from Jefferson Hills to Begijnendijk
The shortest distance (air line) between Jefferson Hills and Begijnendijk is 3,927.74 mi (6,321.09 km).
How far is Jefferson Hills from Begijnendijk
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 21:48 (22.07.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 03:48 (23.07.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,927.74 miles which is equal to 6,321.09 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Begijnendijk, Arr. Leuven, Belgium