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      Distance from Jefferson to Sint-Martens-Lennik

      The shortest distance (air line) between Jefferson and Sint-Martens-Lennik is 4,346.61 mi (6,995.19 km).

      How far is Jefferson from Sint-Martens-Lennik

      Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 22:18 (24.07.2025)

      Sint-Martens-Lennik is located in Arr. Halle-Vilvoorde, Belgium within 50° 47' 60" N 4° 9' 0" E (50.8000, 4.1500) coordinates. The local time in Sint-Martens-Lennik is 04:18 (25.07.2025)

      The calculated flying distance from Sint-Martens-Lennik to Sint-Martens-Lennik is 4,346.61 miles which is equal to 6,995.19 km.

      Jefferson, Georgia, United States

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      Sint-Martens-Lennik, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Martens-Lennik