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      Distance from Jefferson to Sint-Katelijne-Waver

      The shortest distance (air line) between Jefferson and Sint-Katelijne-Waver is 4,355.27 mi (7,009.13 km).

      How far is Jefferson from Sint-Katelijne-Waver

      Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 20:20 (23.07.2025)

      Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 02:20 (24.07.2025)

      The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 4,355.27 miles which is equal to 7,009.13 km.

      Jefferson, Georgia, United States

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      Sint-Katelijne-Waver, Arr. Mechelen, Belgium

      Related Distances to Sint-Katelijne-Waver