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      Distance from Jefferson to Sint-Genesius-Rode

      The shortest distance (air line) between Jefferson and Sint-Genesius-Rode is 4,355.99 mi (7,010.29 km).

      How far is Jefferson from Sint-Genesius-Rode

      Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 16:58 (23.07.2025)

      Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 22:58 (23.07.2025)

      The calculated flying distance from Sint-Genesius-Rode to Sint-Genesius-Rode is 4,355.99 miles which is equal to 7,010.29 km.

      Jefferson, Georgia, United States

      Related Distances from Jefferson

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      Jefferson to Baltimore (Maryland)526.23 mi (846.89 km)
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      Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Genesius-Rode