Distance from Jefferson to Sint-Andries
The shortest distance (air line) between Jefferson and Sint-Andries is 4,297.41 mi (6,916.01 km).
How far is Jefferson from Sint-Andries
Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 17:26 (23.07.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 23:26 (23.07.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,297.41 miles which is equal to 6,916.01 km.
Jefferson, Georgia, United States
Related Distances from Jefferson
Sint-Andries, Arr. Brugge, Belgium