Distance from Jefferson to Opglabbeek
The shortest distance (air line) between Jefferson and Opglabbeek is 4,397.92 mi (7,077.78 km).
How far is Jefferson from Opglabbeek
Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 04:17 (23.07.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 10:17 (23.07.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 4,397.92 miles which is equal to 7,077.78 km.
Jefferson, Georgia, United States
Related Distances from Jefferson
Opglabbeek, Arr. Maaseik, Belgium