Distance from Jefferson to Lyaskovets
The shortest distance (air line) between Jefferson and Lyaskovets is 5,487.81 mi (8,831.78 km).
How far is Jefferson from Lyaskovets
Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 05:05 (26.07.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 12:05 (26.07.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 5,487.81 miles which is equal to 8,831.78 km.
Jefferson, Georgia, United States
Related Distances from Jefferson
Lyaskovets, Veliko Tarnovo, Bulgaria