Distance from Jefferson to Kalmthout
The shortest distance (air line) between Jefferson and Kalmthout is 4,344.49 mi (6,991.78 km).
How far is Jefferson from Kalmthout
Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 13:15 (22.07.2025)
Kalmthout is located in Arr. Antwerpen, Belgium within 51° 22' 59.88" N 4° 28' 0.12" E (51.3833, 4.4667) coordinates. The local time in Kalmthout is 19:15 (22.07.2025)
The calculated flying distance from Kalmthout to Kalmthout is 4,344.49 miles which is equal to 6,991.78 km.
Jefferson, Georgia, United States
Related Distances from Jefferson
Kalmthout, Arr. Antwerpen, Belgium