Distance from Jefferson to Begijnendijk
The shortest distance (air line) between Jefferson and Begijnendijk is 4,366.65 mi (7,027.45 km).
How far is Jefferson from Begijnendijk
Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 16:13 (20.07.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 22:13 (20.07.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,366.65 miles which is equal to 7,027.45 km.
Jefferson, Georgia, United States
Related Distances from Jefferson
Begijnendijk, Arr. Leuven, Belgium