Distance from Jamestown to Steenokkerzeel
The shortest distance (air line) between Jamestown and Steenokkerzeel is 3,810.82 mi (6,132.92 km).
How far is Jamestown from Steenokkerzeel
Jamestown is located in New York, United States within 42° 5' 51.36" N -80° 45' 47.88" W (42.0976, -79.2367) coordinates. The local time in Jamestown is 21:28 (26.07.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 03:28 (27.07.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,810.82 miles which is equal to 6,132.92 km.
Jamestown, New York, United States
Related Distances from Jamestown
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium