Distance from Jamestown to Sint-Andries
The shortest distance (air line) between Jamestown and Sint-Andries is 3,750.53 mi (6,035.89 km).
How far is Jamestown from Sint-Andries
Jamestown is located in New York, United States within 42° 5' 51.36" N -80° 45' 47.88" W (42.0976, -79.2367) coordinates. The local time in Jamestown is 10:47 (25.07.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 16:47 (25.07.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 3,750.53 miles which is equal to 6,035.89 km.
Jamestown, New York, United States
Related Distances from Jamestown
Sint-Andries, Arr. Brugge, Belgium