Distance from Jamestown to Lyaskovets
The shortest distance (air line) between Jamestown and Lyaskovets is 4,936.16 mi (7,943.98 km).
How far is Jamestown from Lyaskovets
Jamestown is located in New York, United States within 42° 5' 51.36" N -80° 45' 47.88" W (42.0976, -79.2367) coordinates. The local time in Jamestown is 10:28 (26.07.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 17:28 (26.07.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 4,936.16 miles which is equal to 7,943.98 km.
Jamestown, New York, United States
Related Distances from Jamestown
Lyaskovets, Veliko Tarnovo, Bulgaria