Distance from Huntington to San Cesareo
The shortest distance (air line) between Huntington and San Cesareo is 1,053.80 mi (1,695.93 km).
How far is Huntington from San Cesareo
Huntington is located in York, United Kingdom within 53° 59' 33.36" N -2° 57' 25.2" W (53.9926, -1.0430) coordinates. The local time in Huntington is 22:40 (20.08.2025)
San Cesareo is located in Roma, Italy within 41° 49' 0.12" N 12° 48' 0" E (41.8167, 12.8000) coordinates. The local time in San Cesareo is 23:40 (20.08.2025)
The calculated flying distance from San Cesareo to San Cesareo is 1,053.80 miles which is equal to 1,695.93 km.
Huntington, York, United Kingdom