Distance from Hickory to Aleksandrow Kujawski
The shortest distance (air line) between Hickory and Aleksandrow Kujawski is 4,672.96 mi (7,520.40 km).
How far is Hickory from Aleksandrow Kujawski
Hickory is located in North Carolina, United States within 35° 44' 27.6" N -82° 40' 39.72" W (35.7410, -81.3223) coordinates. The local time in Hickory is 13:44 (05.09.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 19:44 (05.09.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,672.96 miles which is equal to 7,520.40 km.
Hickory, North Carolina, United States
Related Distances from Hickory
Aleksandrow Kujawski, Włocławski, Poland