Distance from Herenthout to Alexandroupoli
The shortest distance (air line) between Herenthout and Alexandroupoli is 1,230.60 mi (1,980.47 km).
How far is Herenthout from Alexandroupoli
Herenthout is located in Arr. Turnhout, Belgium within 51° 8' 60" N 4° 46' 0.12" E (51.1500, 4.7667) coordinates. The local time in Herenthout is 19:04 (29.10.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 20:04 (29.10.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 1,230.60 miles which is equal to 1,980.47 km.
Herenthout, Arr. Turnhout, Belgium