Distance from Herenthout to Aleksandrow Lodzki
The shortest distance (air line) between Herenthout and Aleksandrow Lodzki is 626.14 mi (1,007.67 km).
How far is Herenthout from Aleksandrow Lodzki
Herenthout is located in Arr. Turnhout, Belgium within 51° 8' 60" N 4° 46' 0.12" E (51.1500, 4.7667) coordinates. The local time in Herenthout is 10:35 (16.11.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 10:35 (16.11.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 626.14 miles which is equal to 1,007.67 km.
Herenthout, Arr. Turnhout, Belgium
Related Distances from Herenthout
Aleksandrow Lodzki, Łódzki, Poland