Distance from Hardinxveld-Giessendam to Aleksandrow Lodzki
The shortest distance (air line) between Hardinxveld-Giessendam and Aleksandrow Lodzki is 617.03 mi (993.02 km).
How far is Hardinxveld-Giessendam from Aleksandrow Lodzki
Hardinxveld-Giessendam is located in Zuidoost-Zuid-Holland, Netherlands within 51° 49' 0.12" N 4° 49' 59.88" E (51.8167, 4.8333) coordinates. The local time in Hardinxveld-Giessendam is 16:24 (12.11.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 16:24 (12.11.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 617.03 miles which is equal to 993.02 km.
Hardinxveld-Giessendam, Zuidoost-Zuid-Holland, Netherlands
Related Distances from Hardinxveld-Giessendam
Aleksandrow Lodzki, Łódzki, Poland