Distance from Hackettstown to Aleksandrow Lodzki
The shortest distance (air line) between Hackettstown and Aleksandrow Lodzki is 4,234.07 mi (6,814.07 km).
How far is Hackettstown from Aleksandrow Lodzki
Hackettstown is located in New Jersey, United States within 40° 51' 14.4" N -75° 10' 27.48" W (40.8540, -74.8257) coordinates. The local time in Hackettstown is 13:37 (05.09.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 19:37 (05.09.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,234.07 miles which is equal to 6,814.07 km.
Hackettstown, New Jersey, United States
Related Distances from Hackettstown
Aleksandrow Lodzki, Łódzki, Poland