Distance from Garfield Heights to Sansepolcro
The shortest distance (air line) between Garfield Heights and Sansepolcro is 4,500.23 mi (7,242.41 km).
How far is Garfield Heights from Sansepolcro
Garfield Heights is located in Ohio, United States within 41° 25' 11.64" N -82° 23' 46.32" W (41.4199, -81.6038) coordinates. The local time in Garfield Heights is 10:16 (24.08.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 16:16 (24.08.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 4,500.23 miles which is equal to 7,242.41 km.
Garfield Heights, Ohio, United States