Distance from Farmingville to Lyaskovets
The shortest distance (air line) between Farmingville and Lyaskovets is 4,748.98 mi (7,642.75 km).
How far is Farmingville from Lyaskovets
Farmingville is located in New York, United States within 40° 50' 20.4" N -74° 57' 34.56" W (40.8390, -73.0404) coordinates. The local time in Farmingville is 07:57 (27.07.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 14:57 (27.07.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 4,748.98 miles which is equal to 7,642.75 km.
Farmingville, New York, United States
Related Distances from Farmingville
Lyaskovets, Veliko Tarnovo, Bulgaria