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      Distance from Fallbrook to San Juan de Aznalfarache

      The shortest distance (air line) between Fallbrook and San Juan de Aznalfarache is 5,846.93 mi (9,409.72 km).

      How far is Fallbrook from San Juan de Aznalfarache

      Fallbrook is located in California, United States within 33° 22' 9.48" N -118° 46' 26.76" W (33.3693, -117.2259) coordinates. The local time in Fallbrook is 01:12 (29.08.2025)

      San Juan de Aznalfarache is located in Sevilla, Spain within 37° 22' 0.12" N -7° 58' 59.88" W (37.3667, -6.0167) coordinates. The local time in San Juan de Aznalfarache is 10:12 (29.08.2025)

      The calculated flying distance from San Juan de Aznalfarache to San Juan de Aznalfarache is 5,846.93 miles which is equal to 9,409.72 km.

      Fallbrook, California, United States

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      San Juan de Aznalfarache, Sevilla, Spain

      Related Distances to San Juan de Aznalfarache