Distance from Eagan to Aleksandrow Kujawski
The shortest distance (air line) between Eagan and Aleksandrow Kujawski is 4,578.02 mi (7,367.61 km).
How far is Eagan from Aleksandrow Kujawski
Eagan is located in Minnesota, United States within 44° 49' 1.2" N -94° 50' 10.32" W (44.8170, -93.1638) coordinates. The local time in Eagan is 09:40 (28.08.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 16:40 (28.08.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,578.02 miles which is equal to 7,367.61 km.
Eagan, Minnesota, United States
Related Distances from Eagan
Aleksandrow Kujawski, Włocławski, Poland