Distance from Dunkirk to Aleksandrow Lodzki
The shortest distance (air line) between Dunkirk and Aleksandrow Lodzki is 4,315.42 mi (6,945.00 km).
How far is Dunkirk from Aleksandrow Lodzki
Dunkirk is located in New York, United States within 42° 28' 48.36" N -80° 40' 3.36" W (42.4801, -79.3324) coordinates. The local time in Dunkirk is 06:17 (05.09.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 12:17 (05.09.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,315.42 miles which is equal to 6,945.00 km.
Dunkirk, New York, United States
Related Distances from Dunkirk
Aleksandrow Lodzki, Łódzki, Poland