Distance from Duncan to Vetraz-Monthoux
The shortest distance (air line) between Duncan and Vetraz-Monthoux is 5,138.74 mi (8,270.00 km).
How far is Duncan from Vetraz-Monthoux
Duncan is located in Oklahoma, United States within 34° 32' 26.88" N -98° 4' 42.6" W (34.5408, -97.9215) coordinates. The local time in Duncan is 20:23 (05.08.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 03:23 (06.08.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 5,138.74 miles which is equal to 8,270.00 km.
Duncan, Oklahoma, United States
Related Distances from Duncan
Vetraz-Monthoux, Haute-Savoie, France