Distance from Drobeta-Turnu Severin to Montechiarugolo
The shortest distance (air line) between Drobeta-Turnu Severin and Montechiarugolo is 600.35 mi (966.16 km).
How far is Drobeta-Turnu Severin from Montechiarugolo
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 13:16 (30.08.2025)
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 12:16 (30.08.2025)
The calculated flying distance from Montechiarugolo to Montechiarugolo is 600.35 miles which is equal to 966.16 km.
Drobeta-Turnu Severin, Mehedinţi, Romania